SOLVED: A three letter password is formed from the characters *, , %, $, @}. How many three letter passwords can be made if repetitions are allowed? If repetitions are not allowed? (2024)

`); let searchUrl = `/search/`; history.forEach((elem) => { prevsearch.find('#prevsearch-options').append(`

${elem}

`); }); } $('#search-pretype-options').empty(); $('#search-pretype-options').append(prevsearch); let prevbooks = $(false); [ {title:"Recently Opened Textbooks", books:previous_books}, {title:"Recommended Textbooks", books:recommended_books} ].forEach((book_segment) => { if (Array.isArray(book_segment.books) && book_segment.books.length>0 && nsegments<2) { nsegments+=1; prevbooks = $(`

  • ${book_segment.title}
  • `); let searchUrl = "/books/xxx/"; book_segment.books.forEach((elem) => { prevbooks.find('#prevbooks-options'+nsegments.toString()).append(`

    ${elem.title} ${ordinal(elem.edition)} ${elem.author}

    `); }); } $('#search-pretype-options').append(prevbooks); }); } function anon_pretype() { let prebooks = null; try { prebooks = JSON.parse(localStorage.getItem('PRETYPE_BOOKS_ANON')); }catch(e) {} if ('previous_books' in prebooks && 'recommended_books' in prebooks) { previous_books = prebooks.previous_books; recommended_books = prebooks.recommended_books; if (typeof PREVBOOKS !== 'undefined' && Array.isArray(PREVBOOKS)) { new_prevbooks = PREVBOOKS; previous_books.forEach(elem => { for (let i = 0; i < new_prevbooks.length; i++) { if (elem.id == new_prevbooks[i].id) { return; } } new_prevbooks.push(elem); }); new_prevbooks = new_prevbooks.slice(0,3); previous_books = new_prevbooks; } if (typeof RECBOOKS !== 'undefined' && Array.isArray(RECBOOKS)) { new_recbooks = RECBOOKS; for (let j = 0; j < new_recbooks.length; j++) { new_recbooks[j].viewed_at = new Date(); } let insert = true; for (let i=0; i < recommended_books.length; i++){ for (let j = 0; j < new_recbooks.length; j++) { if (recommended_books[i].id == new_recbooks[j].id) { insert = false; } } if (insert){ new_recbooks.push(recommended_books[i]); } } new_recbooks.sort((a,b)=>{ adate = new Date(2000, 0, 1); bdate = new Date(2000, 0, 1); if ('viewed_at' in a) {adate = new Date(a.viewed_at);} if ('viewed_at' in b) {bdate = new Date(b.viewed_at);} // 100000000: instead of just erasing the suggestions from previous week, // we just move them to the back of the queue acurweek = ((new Date()).getDate()-adate.getDate()>7)?0:100000000; bcurweek = ((new Date()).getDate()-bdate.getDate()>7)?0:100000000; aviews = 0; bviews = 0; if ('views' in a) {aviews = acurweek+a.views;} if ('views' in b) {bviews = bcurweek+b.views;} return bviews - aviews; }); new_recbooks = new_recbooks.slice(0,3); recommended_books = new_recbooks; } localStorage.setItem('PRETYPE_BOOKS_ANON', JSON.stringify({ previous_books: previous_books, recommended_books: recommended_books })); build_popup(); } } var whiletyping_search_object = null; var whiletyping_search = { books: [], curriculum: [], topics: [] } var single_whiletyping_ajax_promise = null; var whiletyping_database_initial_burst = 0; //number of consecutive calls, after 3 we start the 1 per 5 min calls function get_whiletyping_database() { //gets the database from the server. // 1. by validating against a local database value we confirm that the framework is working and // reduce the ammount of continuous calls produced by errors to 1 per 5 minutes. return localforage.getItem('whiletyping_last_attempt').then(function(value) { if ( value==null || (new Date()) - (new Date(value)) > 1000*60*5 || (whiletyping_database_initial_burst < 3) ) { localforage.setItem('whiletyping_last_attempt', (new Date()).getTime()); // 2. Make an ajax call to the server and get the search database. let databaseUrl = `/search/whiletype_database/`; let resp = single_whiletyping_ajax_promise; if (resp === null) { whiletyping_database_initial_burst = whiletyping_database_initial_burst + 1; single_whiletyping_ajax_promise = resp = new Promise((resolve, reject) => { $.ajax({ url: databaseUrl, type: 'POST', data:{csrfmiddlewaretoken: "vQmcYb4QZ402868ZRtwtEPwxIrI9gLXOUNu2diu9duuiwYeehLb4eTzRou3FC9Y3"}, success: function (data) { // 3. verify that the elements of the database exist and are arrays if ( ('books' in data) && ('curriculum' in data) && ('topics' in data) && Array.isArray(data.books) && Array.isArray(data.curriculum) && Array.isArray(data.topics)) { localforage.setItem('whiletyping_last_success', (new Date()).getTime()); localforage.setItem('whiletyping_database', data); resolve(data); } }, error: function (error) { console.log(error); resolve(null); }, complete: function (data) { single_whiletyping_ajax_promise = null; } }) }); } return resp; } return Promise.resolve(null); }).catch(function(err) { console.log(err); return Promise.resolve(null); }); } function get_whiletyping_search_object() { // gets the fuse objects that will be in charge of the search if (whiletyping_search_object){ return Promise.resolve(whiletyping_search_object); } database_promise = localforage.getItem('whiletyping_database').then(function(database) { return localforage.getItem('whiletyping_last_success').then(function(last_success) { if (database==null || (new Date()) - (new Date(last_success)) > 1000*60*60*24*30 || (new Date('2023-04-25T00:00:00')) - (new Date(last_success)) > 0) { // New database update return get_whiletyping_database().then(function(new_database) { if (new_database) { database = new_database; } return database; }); } else { return Promise.resolve(database); } }); }); return database_promise.then(function(database) { if (database) { const options = { isCaseSensitive: false, includeScore: true, shouldSort: true, // includeMatches: false, // findAllMatches: false, // minMatchCharLength: 1, // location: 0, threshold: 0.2, // distance: 100, // useExtendedSearch: false, ignoreLocation: true, // ignoreFieldNorm: false, // fieldNormWeight: 1, keys: [ "title" ] }; let curriculum_index={}; let topics_index={}; database.curriculum.forEach(c => curriculum_index[c.id]=c); database.topics.forEach(t => topics_index[t.id]=t); for (j=0; j

    Solutions
  • Textbooks
  • `); } function build_solutions() { if (Array.isArray(solution_search_result)) { const viewAllHTML = userSubscribed ? `View All` : ''; var solutions_section = $(`
  • Solutions ${viewAllHTML}
  • `); let questionUrl = "/questions/xxx/"; let askUrl = "/ask/question/xxx/"; solution_search_result.forEach((elem) => { let url = ('course' in elem)?askUrl:questionUrl; let solution_type = ('course' in elem)?'ask':'question'; let subtitle = ('course' in elem)?(elem.course??""):(elem.book ?? "")+"    "+(elem.chapter?"Chapter "+elem.chapter:""); solutions_section.find('#whiletyping-solutions').append(` ${elem.text} ${subtitle} `); }); $('#search-solution-options').empty(); if (Array.isArray(solution_search_result) && solution_search_result.length>0){ $('#search-solution-options').append(solutions_section); } MathJax.Hub.Queue(["Typeset", MathJax.Hub, document.getElementById('search-solution-options')]); } } function build_textbooks() { $('#search-pretype-options').empty(); $('#search-pretype-options').append($('#search-solution-options').html()); if (Array.isArray(textbook_search_result)) { var books_section = $(`
  • Textbooks View All
  • `); let searchUrl = "/books/xxx/"; textbook_search_result.forEach((elem) => { books_section.find('#whiletyping-books').append(` ${elem.title} ${ordinal(elem.edition)} ${elem.author} `); }); } if (Array.isArray(textbook_search_result) && textbook_search_result.length>0){ $('#search-pretype-options').append(books_section); } } function build_popup(first_time = false) { if ($('#search-text').val()=='') { build_pretype(); } else { solution_and_textbook_search(); } } var search_text_out = true; var search_popup_out = true; const is_login = false; function pretype_setup() { $('#search-text').focusin(function() { $('#search-popup').addClass('show'); resize_popup(); search_text_out = false; }); $( window ).resize(function() { resize_popup(); }); $('#search-text').focusout(() => { search_text_out = true; if (search_text_out && search_popup_out) { $('#search-popup').removeClass('show'); } }); $('#search-popup').mouseenter(() => { search_popup_out = false; }); $('#search-popup').mouseleave(() => { search_popup_out = true; if (search_text_out && search_popup_out) { $('#search-popup').removeClass('show'); } }); $('#search-text').on("keyup", delay(() => { build_popup(); }, 200)); build_popup(true); let prevbookUrl = `/search/pretype_books/`; if (is_login) { $.ajax({ url: prevbookUrl, method: 'POST', data:{csrfmiddlewaretoken: "vQmcYb4QZ402868ZRtwtEPwxIrI9gLXOUNu2diu9duuiwYeehLb4eTzRou3FC9Y3"}, success: function(response){ previous_books = response.previous_books; recommended_books = response.recommended_books; build_popup(); }, error: function(response){ console.log(response); } }); } else { let prebooks = null; try { prebooks = JSON.parse(localStorage.getItem('PRETYPE_BOOKS_ANON')); }catch(e) {} if (prebooks && 'previous_books' in prebooks && 'recommended_books' in prebooks) { anon_pretype(); } else { $.ajax({ url: prevbookUrl, method: 'POST', data:{csrfmiddlewaretoken: "vQmcYb4QZ402868ZRtwtEPwxIrI9gLXOUNu2diu9duuiwYeehLb4eTzRou3FC9Y3"}, success: function(response){ previous_books = response.previous_books; recommended_books = response.recommended_books; build_popup(); }, error: function(response){ console.log(response); } }); } } } $( document ).ready(pretype_setup); $( document ).ready(function(){ $('#search-popup').on('click', '.search-view-item', function(e) { e.preventDefault(); let autoCompleteSearchViewUrl = `/search/autocomplete_search_view/`; let objectUrl = $(this).attr('href'); let selectedId = $(this).data('objid'); let searchResults = []; $("#whiletyping-solutions").find("a").each(function() { let is_selected = selectedId === $(this).data('objid'); searchResults.push({ objectId: $(this).data('objid'), contentType: $(this).data('contenttype'), category: $(this).data('category'), selected: is_selected }); }); $("#whiletyping-books").find("a").each(function() { let is_selected = selectedId === $(this).data('objid'); searchResults.push({ objectId: $(this).data('objid'), contentType: $(this).data('contenttype'), category: $(this).data('category'), selected: is_selected }); }); $.ajax({ url: autoCompleteSearchViewUrl, method: 'POST', data:{ csrfmiddlewaretoken: "vQmcYb4QZ402868ZRtwtEPwxIrI9gLXOUNu2diu9duuiwYeehLb4eTzRou3FC9Y3", query: $('#search-text').val(), searchObjects: JSON.stringify(searchResults) }, dataType: 'json', complete: function(data){ window.location.href = objectUrl; } }); }); });
    SOLVED: A three letter password is formed from the characters *,    , %, $, @}. How many three letter passwords can be made if repetitions are allowed? If repetitions are not allowed? (2024)

    FAQs

    How many 3-letter passwords can be made if repeats are not allowed? ›

    There are 15,600 different 3-letter passwords, with no letters repeating, that can be made using the letters a through z. A 3-letter password, with no letters repeating, using the letters a through z, is simply a permutation of 3 letters taken from the alphabet, which has 26 letters.

    How many 3-letter passwords can be made using the letters a through z if repetition of letters is allowed? ›

    Expert-Verified Answer

    If repetition is allowed then the required passwords generated are 17576.

    How many three letter computer passwords can be formed? ›

    Answer and Explanation:

    Therefore the problem involves permutations. Therefore there are 210 different three-letter passwords that can be formed from the letters { S , T , U , W , X , Y , Z } if no repetition of letters is allowed.

    How many 4 letter passwords can be formed with 7 different letters if no repetition is allowed? ›

    840 is the required answer.

    How many 3-digit alphanumeric combinations are there? ›

    Answer and Explanation:

    The alphabet has 26 letters, and there are 10 number possibilities between 0 and 9, making 36 possible options for each character. To determine how many combinations are possible for a 3-character sequence, multiply 36 x 36 x 36, which equals 46,656 possible combinations.

    How many possible combinations are there of 3 letters and 3 numbers? ›

    Each of the three letter combinations can be combined with any of the three number combinations so the total is 17,576 x 1000 = 17,576,000 different combinations possible.

    What is the 3 character in a password? ›

    Creating a password that contains a minimum of 3 character classes means that you must include at least one character from 3 of the 5 different categories. For example, HJK-0109 is a good password because it contains characters from 3 different groups.

    How many 3-character alphanumeric passwords can be made of capitalization is unique? ›

    Answer and Explanation:

    That is, there will be 26 lowercase letters, 26 uppercase letters, and 10 digits. Thus, if the password is case sensitive, then there are a total of 226,920 possible passwords.

    How many combinations are there with 3 numbers and 2 letters? ›

    So for a license plate which has 2 letters and 3 digits, there are: 26×26×10×10×10=676,000 possibilities.

    Are 3 word passwords safe? ›

    Using three random words is certainly a much better way of securing your data than using one word or common sequence that is easy for both humans and computers to guess.

    How many letters in a password? ›

    At least 12 characters long but 14 or more is better. A combination of uppercase letters, lowercase letters, numbers, and symbols. Not a word that can be found in a dictionary or the name of a person, character, product, or organization.

    How many unique 3 digit codes can be created from the 5 digits 1, 2, 3, 4, 5 if repeats are possible? ›

    Therefore, 5*5*5 = 125 such 3-digit codes are possible. We will have 25 codes starting with 1: 111 to 155, and similarly 25 codes starting with each of the other 4 digits, which confirms the total of 5*25 = 125. The lowest code is 111, and the highest is 555.

    What are 7 characters in a password? ›

    A seven-character computer password can be any three letters of the alphabet, followed by two numerical digits, followed by two more letters. The password is not case sensitive and repeats are allowed. For example: A b C 11 a a is the same as a b c 11 a a .

    How many 4-digit even numbers can be created from the digits 0, 1, 2, 3? ›

    Therefore, there are 96 4-digit even numbers that can be created from the digits {0, 1, 2, 3}.

    How many 3 letter words with or without signature if repetition is not allowed? ›

    Hence, the number of 3-letter words (with or without meaning) formed by using these letters = 10P3=10×9×8=720.

    How many different computer passwords are possible if digits and letters can be repeated 3 digits followed by 4 letters? ›

    There are 10 options for each digit and 26 options for each letter. To find the total number of different passwords, we multiply these options together: 10 * 10 * 10 * 26 * 26 * 26 * 26 = 45,697,600 different passwords possible.

    How many passwords are possible with 4 digits without repeating? ›

    Answer and Explanation:

    Since there's no digit repetition is possible, we use the permutation formula to calculate the number of passwords: n P r = n ! ( n − r ) ! There are 5040 possible passwords.

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